anonymous
  • anonymous
Use Synthetic Division to divide x^2 + 10x + 21 by x + 3 x + 7 x - 7 7x + 21 7x - 21 Question 2 Use synthetic division to find the remainder when 4 - 5x - x^2 + 6x^3 is divided by 3x - 2 -1 4 0 2 Question 3 Use Synthetic Division to find the remainder when 6x^4 + 5x^3 + 3x - 5 is divided by 3x^2 - 2x 0 3x^2 - 2x 7x - 5 2 Question 4 Use synthetic division to divide 5x^3 + 6^x + 8 by x + 2 5x -10 + 26/(x + 2) -44 5x^2 - 10x + 26 5x^2 - 10x + 26 -44/(x + 2) Question 5 Divide us
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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roadjester
  • roadjester
synthetic division only works if you have x-a. You can't have a constant attached to x. Therefore, you can't use synthetic division on question 2 or question 3.
anonymous
  • anonymous
Can you help me with 1 and 4
roadjester
  • roadjester
Umm, what do the extra numbers and functions mean?

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roadjester
  • roadjester
When you use synthetic division (my syntax is probably off) you usually have:\[{ax^n \pm bx^{n-1} \pm ...a}\over {x-a}\]
roadjester
  • roadjester
The a and b are just constants but the syntax is way off...
anonymous
  • anonymous
there the answer choices
roadjester
  • roadjester
ah, I see, you should have labeled them...I was like wth.
roadjester
  • roadjester
and I keep losing my connection dammit!
roadjester
  • roadjester
ok, in synthetic division, you use only constants, but what you're dividing by must be in the form of x-a or x+a
roadjester
  • roadjester
-3 1 10 21 _________-3____-21_________________________________________________________ 1 7 0
roadjester
  • roadjester
Therefore your answer to question 1 is x+7
roadjester
  • roadjester
-2 5 6 0 8 -10 8 -16 ____________________________________ 5 -4 8 -8 So 5x^2-4x+8 with a remainder of \[-8\over {x+2}\]
roadjester
  • roadjester
Basically, the first number (constant) is just dropped down. Then, you multiply it by the number in the corner. In this case, since you were dividing by x+a, the number in the upper left corner is -a. After you multiply, place it underneath the next constant and add the two numbers. The sum goes beneath the dotted line and that number is multiplied by -a and the process is repeated. If your final number (under the line) is 0, there is no remainder. If there is a number, that's your remainder.
roadjester
  • roadjester
oops, I flipped the constants for x and x^2. My bad.
roadjester
  • roadjester
-2 5 0 6 8 -10 20 -52 ____________________________________ 5 -10 26 -44
roadjester
  • roadjester
Remainder is \[-44\over {x+2}\]

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