use the given transformation to evaluate the integral. u=x+y, v=-2x+y; integrateR: 2y dx dy where R is the parallelogram bounded by the lines y=1-x, y=4-x,y=2x+2,y=2x+5.
I have already transformed the region into a square that intersects at (1,2), (4,2), (1,5), (4,5). I need help with setting up the integrals for calculation.

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I am unsure of how you did that, I haven't had algebra class in quite a few years.

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