anonymous
  • anonymous
1.(4x/9)+(x-10/9) 2.(t^2+6t/t-1)-(7/t-1) Show work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I'll rewrite this because I can't see why the ( ) are where they are right now 1. 4x/9 +(x-10)/9 and 2. (t^2+6t)/(t-1) - 7/(t-1) is this correct?
anonymous
  • anonymous
it supposed to be in fraction format
anonymous
  • anonymous
with the order of operations, you need to write it the way I did, else, for example, the second term in 1 would x (undivided by 9) - 10/9. Anyways, so, since you have the same denominator for both, you can all put it in the same fraction : 1. (4x+x-10)/9 = (5x-10)/9 2. (t^2+6t-7)/(t-1) makes sense?

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anonymous
  • anonymous
its addition and substraction of rational expressions
anonymous
  • anonymous
|dw:1333388296003:dw|
anonymous
  • anonymous
first one
anonymous
  • anonymous
ok, great, so my first answer was right. 1. (4x+x-10)/9 = (5x-10)/9 2. (t^2+6t-7)/(t-1) And, unless you've learned to divide polynomials, you're pretty much done
anonymous
  • anonymous
i need help cause i don't know how to do this
anonymous
  • anonymous
1. 4X/9 + X-10/9 MY ANS: 5(X-2)/9 BAD 4x/9+x-10/9= 4x/9+9x/9-10/9= (13x-10)/9 2. T^2+6T/T-1 - 7/T-1 MY ANS: T + 7 BAD again, can't you use brackets? T^2+6T/T-1 - 7/T-1=T^2+6-1-7/T-1= T^2+4-7/T=(T^3+4T-7)/T If you mean T^2+6T/(T-1) - 7/(T-1)= [T^2(T-1)+6T-7]/(T-1)= (T^3-T^2+6T-7)/(T-1) 3. 3/X + 13/X-11 MY ANS: 16X-33/X(X-11) WORSE Should be [3(X-11)+13(X-11)]/[X*(X-11)]= (16X-11*16)/ [X*(X-11)] (16X-176) / [X*(X-11)] 4. 4/4x^2y -y/14xz MY ANS:-2XY^2+35Z/ 28X^2YZ BAD (4*7Z-Y*2XY)/(28X^2YZ)= (28Z-2XY^2)/(28X^2YZ)= (14Z-XY^2)/(14X^2YZ) 5.x^2+2x/12x+54 - 3-x/8x+36 MY ANS:X-1/12 x^2+1/6+54-3-1/8+36= X^2+87+(3-2)/18= X^2+87+1/18 WITHOUT COMMENT 6.2/x^2+8x+15+1/x^2+11x+30 MY ANS:3/(X+6)(X+3) VERY, VERY BAD 2/x^2+8x+15+1/x^2+11x+30= (2/x^2+1/x^2)+(8x+11x)+(15+30)+1/x^2= 3/x^2+19x+45= (3+19x+45x^2)/x^2 7. Using complete sentences, explain why it is necessary to have common denominators when adding or subtracting rational expressions Sorry but I am a mathematition and I can't use complete sentences. 8. Using complete sentences, explain why it is necessary to have a strong foundation in factoring when working with rational expressions. a/a hope this helps!! :-)

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