anonymous
  • anonymous
[(x-3)+y] [(x-3)+y] I got two answers for these problems which one is correct? x^2 - 6x +y^2 and x^2 -6x +9 + 2xy + y^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Shayaan_Mustafa
  • Shayaan_Mustafa
both will be correct. coz it seems like quadratic equation dear.
anonymous
  • anonymous
\[\Large [(x-3)+y]\cdot [(x-3)+y]=(x-3+y)\cdot (x-3+y)\] \[\Large x^2-3x+xy-3x+9-3y+xy-3y+y^2\] \[\Large x^2-6x-6y+2xy+9+y^2\]
Shayaan_Mustafa
  • Shayaan_Mustafa
@Kreshnik how you magnify your equations? when you write equation then it becomes large font. how?

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anonymous
  • anonymous
\[\huge x^2-4+23...\] --- this one was \huge then write equation... I write mostly with .. \Large ... BUT sometimes \LARGE THE ONE YOU ASKED WAS TYPED WITH \Large :)
anonymous
  • anonymous
neither of your answer is correct. @Kreshnik's answer is the right answer.
Shayaan_Mustafa
  • Shayaan_Mustafa
i don't understand. can you kindly make a syntax for this?
anonymous
  • anonymous
syntax means ?? :( @Shayaan_Mustafa ... (Do you know to use Latex , down you have Equation button see??)
Shayaan_Mustafa
  • Shayaan_Mustafa
yes. i can see. i know latex.
anonymous
  • anonymous
.... Here's an example ... \Large x^2-2+4 \cdot 0 Copy this and click Equation button... then PASTE , Enjoy. ;)
Shayaan_Mustafa
  • Shayaan_Mustafa
\[\huge x ^{2}\]
anonymous
  • anonymous
\[\Large x^2-2+4 \cdot 0\]
Shayaan_Mustafa
  • Shayaan_Mustafa
aha. thnx. thnx a lot. i got it.
anonymous
  • anonymous
@Shayaan_Mustafa Well done !!

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