aroub
  • aroub
In a ship race Hana completed 20 km downstream in 3 hr. If the return trip took 4 hr 20 min, how fast can she paddle in still water?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Hero
  • Hero
d = rt 20 = 3(r+w) 20 = (13(r+w))/3
aroub
  • aroub
Yes, this is what I did and then got a negative answer!
Hero
  • Hero
well, the second equation is supposed to be r - w for upstream

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Hero
  • Hero
Let me finish solving
aroub
  • aroub
Okay
aroub
  • aroub
nvm, I think I did something wrong in the calculations -.-
anonymous
  • anonymous
Calculated in jiffy, by any chance is it \( \frac{220}{39} km/hr\)?
Hero
  • Hero
FFM, I would swear that your comment is a violation of the code of conduct.
Hero
  • Hero
Posting answers, with no steps and butting in while someone else is trying to help.
aroub
  • aroub
I got 95/3
anonymous
  • anonymous
No need to get all bummed up. I was just testing my mind.
anonymous
  • anonymous
Here is how I got that : \[ x+y= 20/3 \] \[ x-y= 20\left/\frac{13}{3}\right. \] No solving for \( x\)
anonymous
  • anonymous
now*
Hero
  • Hero
Yeah, I meant to do it that way
aroub
  • aroub
But you'll get x AND y, what do you do?
anonymous
  • anonymous
x = speed in still water y= speed of the steam/river
Hero
  • Hero
That's why I used r and w
Hero
  • Hero
Did anybody get r = 5.64103 and w = 1.02563
aroub
  • aroub
FFM did!
aroub
  • aroub
Okay.. Thanks a lot!!

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