anonymous
  • anonymous
Solve the equation: (3y+2)(y+3)=y+14 Please show work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
multiply out the left side then make 1 side zero. solve the quadratic.
anonymous
  • anonymous
Okay thanks
anonymous
  • anonymous
\[\Large (3y+2)(y+3)=y+14\] multiply left side and you'll get... \[\Large 3y^2+9y+2y+6=y+14\] from here you go... \[\Large 3y^2+11y+6-y-14=0\] we moved the left side to the right and changed signs... now you have quadratic equation... \[\Large 3y^2+10y-8=0\] Now use this formula... \[\LARGE x_{1/2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] you have a=3 b=10 and c=-8 just substitute and there you go !... ;)

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