anonymous
  • anonymous
Find the volume of the solid generated by revolving the region bounded by the graphs of y=sqrt x and y=o and x = 4 about the y axis.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1333396585172:dw| you want shell method or washer method?
anonymous
  • anonymous
shell please
anonymous
  • anonymous
ok

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More answers

anonymous
  • anonymous
|dw:1333396773690:dw|
anonymous
  • anonymous
|dw:1333396902417:dw|
anonymous
  • anonymous
can you finish it from here?
anonymous
  • anonymous
Switch 4 and root x
anonymous
  • anonymous
could you show me the washer method too?
anonymous
  • anonymous
sure...
campbell_st
  • campbell_st
look at the value x = 4 substituting y = 2 since the domain is x>=0 range y >= 0 the question can be solved by rewriting thr equation \[x = y^2\] where y > 0 the problem is now \[V = \pi \int\limits_{0}^{2} y^4 dy\]
anonymous
  • anonymous
|dw:1333397042172:dw|
anonymous
  • anonymous
|dw:1333397194912:dw|
anonymous
  • anonymous
the answer should be the same...
anonymous
  • anonymous
why is R 4? is that the x=4?
campbell_st
  • campbell_st
the answer is 32pi/5 units cubed
anonymous
  • anonymous
R=4 ? that's the outer radius. r=x is the inner radius.
anonymous
  • anonymous
the answer is supposed to be 128pi/5
anonymous
  • anonymous
that's what i got for the washer (2nd method). checking shell method answer now...
anonymous
  • anonymous
yep, same...
anonymous
  • anonymous
i'm saying, is 4 the outer radius because that's what it's bounded by? the x=4 in the original requirements?
anonymous
  • anonymous
yes..
anonymous
  • anonymous
depending on the representative rectangle, dy, R is always 4 but r changes.
anonymous
  • anonymous
okey dokey. thanks a lot, this makes a lot more sense now
anonymous
  • anonymous
yw...:)

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