anonymous
  • anonymous
https://www.connexus.com/content/media/459431-3172011-13026-PM-25179049.png someone please help? so confused
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Shayaan_Mustafa
  • Shayaan_Mustafa
LOL :p
anonymous
  • anonymous
what do you have to do? simplify it?
anonymous
  • anonymous
yah

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anonymous
  • anonymous
my equation writer is playing up
Hero
  • Hero
In order to solve this problem you need to know how to do the following: 1. Divide fractions 2. Divide exponents 3. Square root properties 4. Exponent properties Which of the following do you not know?
radar
  • radar
\[\sqrt{9x ^{14}y ^{-2}}\]There is a start.
radar
  • radar
Another start \[3x ^{7}\sqrt{1/y ^{2}}\] Whats left to do? It can be further simplified.
radar
  • radar
You wrap it up.
anonymous
  • anonymous
the rules you need to know are: \[\sqrt{x} = x^{\frac{1}{2}}\] \[x^a \times x^b = x^{a+b}\] \[\frac{1}{x^c} = x^{-c}\]which implies \[\frac{x^a}{x^b} = x^{a-b}\] finally:\[(x^a)^b =x^{ab}\]
anonymous
  • anonymous
using those rules you can group the powers of x and y together until it looks simpler
anonymous
  • anonymous
try not to be confused by the fact that i used x to express those rules, by that i meant it works for any number, so it works for y as well
radar
  • radar
To explain further what I started 63/7 = 9 That is where the 9 came from fractional division. \[x ^{15}/x=x ^{15}/x ^{1}=x ^{(15-1)}=x ^{14}\]\[y ^{9}\over y ^{11}\]is the same as \[y ^{(9-11)}y ^{-2}\]
Directrix
  • Directrix
|dw:1333401520373:dw|
radar
  • radar
All of this is still under the radical.
radar
  • radar
You have received lots of help, it is up to you to learn it.
Directrix
  • Directrix
|dw:1333401692797:dw|
Directrix
  • Directrix
That's (3 x^7 )/ y Question?
anonymous
  • anonymous
thankyou everyone for the help helped so much

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