A = {(a,b,c) where a + b = 2c}
Find a basis for A

A = {(a,b,c) where a + b = 2c}
Find a basis for A

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But then that would make c always 0, wouldn't it? That doesn't seem right...

(a,0,1/2a) (0,b,1/2b)

i think this should do

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