anonymous
  • anonymous
Equation for an ellipse with center (0,0), vertices (3,0) and (-3,0), and foci (2,0) and (-2,0)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
a. x^2/9+y^2/4=1 b. x^2/5+y^2/9=1 c. x^2/9+y^2/5=1 d. x^2/4+y^2/9=1
NotTim
  • NotTim
dunno what a foci is
NotTim
  • NotTim
really, i dunno what this is in general

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NotTim
  • NotTim
may i offer the services of wolfram alpha to help?
anonymous
  • anonymous
At this point PLEASE!
anonymous
  • anonymous
Can you provide me with a link
amistre64
  • amistre64
|dw:1333407979574:dw|
amistre64
  • amistre64
center to vertex = 3 center to focus = 2 a^2 = 3^2 + 2^2 = 13 a = sqrt(13); so we should have a 9 and a 13 in the denoms
amistre64
  • amistre64
hmmm
amistre64
  • amistre64
the denoms measure the 1/2 axis after we sqrt them
amistre64
  • amistre64
sqrt(9) = 3 sqrt(n) = sqrt(13); n = 13 what am i missing?
anonymous
  • anonymous
Hmm... I'm just confused. But I understand your useful explanation
amistre64
  • amistre64
|dw:1333408216198:dw| i had my verts in the wrong spots :)
amistre64
  • amistre64
9-4 = 5 sqrt(5)^2 = 5 x/9 and y/5 should do it
anonymous
  • anonymous
Oh o.k. Now it makes sense. Thanks amistre64. You're the best
amistre64
  • amistre64
good luck

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