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math456

  • 2 years ago

I need help, anyone?

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  1. math456
    • 2 years ago
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    Q. 2,3, 5?

  2. Kreshnik
    • 2 years ago
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    do you have a graph yet? ... I can get you one !

  3. math456
    • 2 years ago
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    |dw:1333410736966:dw| yea its like this!

  4. Kreshnik
    • 2 years ago
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    ...

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  5. math456
    • 2 years ago
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    ohh i c :)

  6. math456
    • 2 years ago
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    so for Q.2 we have to graph the inverse, right?

  7. Kreshnik
    • 2 years ago
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    is this what is required at option a)?? ...I don't get it well enough (I'm not American/British :S )

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  8. Kreshnik
    • 2 years ago
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    two lines... f(x)=4x-8 and y=x

  9. math456
    • 2 years ago
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    umm we have to find inverse first which is x+8/4=y and graphing it gives me |dw:1333411085687:dw|

  10. Kreshnik
    • 2 years ago
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    \[\Large f^{-1}(x) =\frac{1}{f(x)}\] ... so that should be . .\[\LARGE f^{-1}(x)=\frac{1}{4x-8}\] is it??

  11. math456
    • 2 years ago
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    and ur graph is answer to part 5

  12. math456
    • 2 years ago
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    umm our teacher tell us that u switch letters first & then solve for y to get the inverse..

  13. math456
    • 2 years ago
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    do u know how to do Q.3?

  14. Kreshnik
    • 2 years ago
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    I know it like I wrote it !! O_O ... show me your way then!

  15. Kreshnik
    • 2 years ago
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    are you there?

  16. math456
    • 2 years ago
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    yea

  17. math456
    • 2 years ago
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    i already told u inverse seems like x+8/4=y

  18. math456
    • 2 years ago
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    or f^-1(x)

  19. math456
    • 2 years ago
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    what does it mean to test the symmetry accross the line y=x?

  20. Kreshnik
    • 2 years ago
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    I don't know it either... but tell me, how do you get x+8/4=y ... show me steps I want to see them if it's possible ! O_O

  21. math456
    • 2 years ago
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    lol okay..

  22. math456
    • 2 years ago
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    y=f(x)=4x-8 x=4y-8 (switched) x+8/4=y (solve for y)

  23. Kreshnik
    • 2 years ago
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    still dizzy... I don't know.. OK now tell me if we have \[\LARGE f(x)=\frac{1-x}{1+x}\] how does f^{-1} go?

  24. slaaibak
    • 2 years ago
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    the inverse of f(x) is not 1/f(x)

  25. Kreshnik
    • 2 years ago
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    ok I guess I'm wrong, but I want to learn it.. :(

  26. slaaibak
    • 2 years ago
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    To find the inverse, switch x and y, and write in terms of y.

  27. Kreshnik
    • 2 years ago
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    well then @math456 is right !!...

  28. math456
    • 2 years ago
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    f(x)=1-x/1+x x=1-y/1+y x(1+y)=1-y x+xy=1-y y=1-x+xy

  29. math456
    • 2 years ago
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    y=1-x-xy*

  30. math456
    • 2 years ago
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    ????

  31. slaaibak
    • 2 years ago
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    y = (1 - x)/(1 + x) Switching the x and y: x = (1-y)/(1+y) x + xy = 1 - y y(1+x) = 1-x y = (1-x)/(x+1)

  32. slaaibak
    • 2 years ago
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    with which number do you need help with?

  33. math456
    • 2 years ago
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    Q.2 a,b

  34. math456
    • 2 years ago
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    i mean like for a we hv to reflect the graph of f across the diagonal line y=x, how?

  35. slaaibak
    • 2 years ago
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    draw the y=x line and flip the line over it

  36. slaaibak
    • 2 years ago
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    I mean, flip it over the line

  37. math456
    • 2 years ago
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    |dw:1333412317919:dw| like this?

  38. math456
    • 2 years ago
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    fliping it will be|dw:1333412361021:dw|

  39. slaaibak
    • 2 years ago
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    That's y=x yes. Best way to see it is to draw the line, then folding the paper over y=x and to see how the graph reflects

  40. slaaibak
    • 2 years ago
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    Noo... you flip the function f(x) over the line y=x.

  41. math456
    • 2 years ago
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    so for Q2a we hv to flip over the f(x) ?

  42. math456
    • 2 years ago
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    or the inverse?

  43. slaaibak
    • 2 years ago
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    flip f(x) over y=x

  44. math456
    • 2 years ago
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    ohh okay!

  45. math456
    • 2 years ago
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    |dw:1333412477378:dw| so its gona be like this?

  46. math456
    • 2 years ago
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    how about 2b? and question 5 ask the same thing as 2a, right?

  47. slaaibak
    • 2 years ago
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    noooo |dw:1333412696801:dw|

  48. slaaibak
    • 2 years ago
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    question 2 b: get a few points (x,y) then change them to (y,x) and draw them

  49. math456
    • 2 years ago
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    and 5 is |dw:1333412939248:dw| ?

  50. slaaibak
    • 2 years ago
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    Not exactly sure what they mean..

  51. math456
    • 2 years ago
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    so for 2b i got a graph like this |dw:1333413313588:dw|

  52. slaaibak
    • 2 years ago
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    ... I honestly don't know how you got that. Look at my graph. Thats how f, y=x and f^-1 looks like

  53. math456
    • 2 years ago
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    that was for f(x) and if I reflect it, i'll get |dw:1333413484096:dw|

  54. math456
    • 2 years ago
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    with Question 5?

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