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ihatealgebrasomuch

  • 4 years ago

how do i solve this by factoring? w(w-3)=108

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  1. Eluss
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=solve+w%28w-3%29%3D108+for+w

  2. inkyvoyd
    • 4 years ago
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    w^2-3w-108=0 Now we are looking for the factors of 108 that are 3 from each other.

  3. inkyvoyd
    • 4 years ago
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    Let's try 12*9

  4. Somjit
    • 4 years ago
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    w^2-3w-108=0 w^2-12w+9w-108=0 W(w-12)+9(w-12)=0(w-12)(w-9)=0 w=12,9

  5. inkyvoyd
    • 4 years ago
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    (w+9)(w-12) or (w-9)(w+12)

  6. inkyvoyd
    • 4 years ago
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    since we see -3w, we have (w+9)(w-12).

  7. inkyvoyd
    • 4 years ago
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    Not what @Somjit said xD.

  8. ihatealgebrasomuch
    • 4 years ago
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    k got it, thx sooo much

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