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Eluss Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=solve+w%28w3%29%3D108+for+w
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
w^23w108=0 Now we are looking for the factors of 108 that are 3 from each other.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Let's try 12*9
 2 years ago

Somjit Group TitleBest ResponseYou've already chosen the best response.0
w^23w108=0 w^212w+9w108=0 W(w12)+9(w12)=0(w12)(w9)=0 w=12,9
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
(w+9)(w12) or (w9)(w+12)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
since we see 3w, we have (w+9)(w12).
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.0
Not what @Somjit said xD.
 2 years ago

ihatealgebrasomuch Group TitleBest ResponseYou've already chosen the best response.0
k got it, thx sooo much
 2 years ago
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