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.Sam.Best ResponseYou've already chosen the best response.1
\[\frac{\partial^2 \Phi}{\partial x^{2}}+\frac{\partial^2 \Phi}{\partial y^2}=f'(z)^2(\frac{\partial^2 \Phi}{\partial u^2}+\frac{\partial^2 \Phi}{\partial v^2})\]
 2 years ago

KreshnikBest ResponseYou've already chosen the best response.1
wahh... I'm ready to faint !! LOL , I don't know :P
 2 years ago

agreeneBest ResponseYou've already chosen the best response.0
unfortunatelygoogle books is missing a rather needed page, but yah. http://books.google.com/books?id=1DItN16tMC&pg=PA366&lpg=PA366&dq=%22%E2%88%82%5E2%CE%A6/%E2%88%82x%5E2%2B%E2%88%82%5E2%CE%A6/%E2%88%82y%5E2%3D%7Cf%E2%80%B2(z)%7C%5E2(%E2%88%82%5E2%CE%A6/%E2%88%82u%5E2%2B%E2%88%82%5E2%CE%A6/%E2%88%82v%5E2)%22&source=bl&ots=bLDvOGPmRR&sig=5rgnEEIWehIwfj0OaDZE1Kp4VE&hl=en&sa=X&ei=Glx6T5KCJsfi2AXa3vycAw&ved=0CCEQ6AEwAA#v=onepage&q&f=false
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.2
WTH! I'm just a 15 year old self studying calc two. I DON GET THOSE FUNNY PHI AND PARTIAL DERIVATIVE SIGNS! :(
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.2
That is, if that is even phi :S
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.1
I thought you know because you'd say ERF(), sorry
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.2
I only know what the erf is because I wanted to figure out the empirical rule by indefinite integration, and later I realized that to be impossible.
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.2
Cause wolfram alpha said so :)
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.2
Good luck though, try reddit's r/cheatatmathhomework
 2 years ago

inkyvoydBest ResponseYou've already chosen the best response.2
They can do group theory there, i'm not sure why.
 2 years ago
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