anonymous
  • anonymous
What is the length of the transverse axis? (y-2)^2/(16) - (x+1)^2/(144) =1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
which ones transverse?
amistre64
  • amistre64
-x^2 never can equal a +1 so the only axis we cross is the y axis; so if we double the sqrt of the denom under y that should do it
anonymous
  • anonymous
so you take y-2^2 and 144 and do what

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amistre64
  • amistre64
the 144 is under the x stuff so i dont think its gonna be important; but that might be the althimerz talking 16 is under the y spot. sqrt(16) = 4 ; this should be half the distance we want, so double it
anonymous
  • anonymous
I'm confused the square root of 16 is 4 but you want me to double it? so would it be 4(4) or 4(2) making 8?
amistre64
  • amistre64
4 doubled is 8

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