anonymous
  • anonymous
Circle S has an equation of (x + 16)^2 + (y – 9)^2 = 4. What is the center and radius of circle S? Answer Center: (16, -9); Radius: 4 Center: (-16, 9); Radius: 4 Center: (16, -9); Radius: 2 Center: (-16, 9); Radius: 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
do you know the formula of the circle ?
anonymous
  • anonymous
\[(x-h)^2+(y-k)^2=r^2\] where (h,k) is the center and r is the radius
anonymous
  • anonymous
want to take a stab at the answer, tahtah?

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amistre64
  • amistre64
thats why i just call h Cx and k Cy
anonymous
  • anonymous
uhhhhhhmmmmmmmm one sec
anonymous
  • anonymous
you have it in just the form you want \[(x + 16)^2 + (y – 9)^2 = 4\] \[(x-h)^2+(y-k)^2=r^2\]
anonymous
  • anonymous
identify h, k and r
anonymous
  • anonymous
would it be A?
anonymous
  • anonymous
definitely not a, because r^2=4 r=2
anonymous
  • anonymous
Oh im slow. So is it C then?
anonymous
  • anonymous
@Dockworker \[\Large if \quad r^2=4 \longrightarrow r=\pm\sqrt{4} \quad ??\]
anonymous
  • anonymous
not c either, its d you can rewrite the equation to better help you see \[(x-(-16))^2+(y-9)^2=2^2\]
anonymous
  • anonymous
@Kreshnik, we're dealing with a radius here. you can discard the negative value.
anonymous
  • anonymous
:P
anonymous
  • anonymous
oh darn i was not close at all. Thank you <3
anonymous
  • anonymous
\[r^2=4\implies r=2\] \[16=-h\implies h=-16\] \[-9=-k\implies k=9\] center is \((-16,9)\) radius is 2

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