anonymous
  • anonymous
Find the indefinite integral of: [arctanx]/[x^2] dx. I would like a hint. NOT the answer please.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Parts?
TuringTest
  • TuringTest
seems promising
anonymous
  • anonymous
|dw:1333424004390:dw|

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anonymous
  • anonymous
Then I get this annoying: [x^3]/[3 + 3x^2]dx for the integral of vdu when it is expanded..
anonymous
  • anonymous
OH! Nevermind.
anonymous
  • anonymous
The antiderivative of x^-2 is NOT x^3/3. I just realized.
anonymous
  • anonymous
Ok so I get now for the integral of vdu: [1]/[(x^2 + 1)(x)] dx Is this partial fraction decomposition, or is there any other way?
anonymous
  • anonymous
I would create two integrals now
anonymous
  • anonymous
partial fractional decomp sounds good
anonymous
  • anonymous
Got it, via partial fraction decomp?
TuringTest
  • TuringTest
I would do partial fractions, but if mathg8 has a better idea I'm all ears
anonymous
  • anonymous
|dw:1333424610903:dw|
TuringTest
  • TuringTest
I dunno, let me check your work...
anonymous
  • anonymous
|dw:1333424732354:dw|
TuringTest
  • TuringTest
yeah it;s right
anonymous
  • anonymous
Expanding and setting the coeff's equal to each other (LHS = RHS), I get A = -1, B = 0, C = 1
anonymous
  • anonymous
did you get the answer yet ?
anonymous
  • anonymous
Yes

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