anonymous
  • anonymous
A particle moves along the x-axis so that at any time t, its position is given by x(t) = 1/2 sint+cos (2t). What is the acceleration of the particle at t=pi/2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1333424198754:dw|
anonymous
  • anonymous
Acceleration is the second derivative of the position.
anonymous
  • anonymous
derivative of sint is cost derivative of cost is -sint v(t) is 1st derivative a(t) is 2nd derivative

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anonymous
  • anonymous
use the chain rule with cos(2t) as well
anonymous
  • anonymous
to get the derivative of x(t), what happens to the 1/2, does it just disappear? And is ther derivative of cos(2t) = -2sin (2t)?
anonymous
  • anonymous
You move the constants outside the derivative.
anonymous
  • anonymous
1/2 doesn't disappear
anonymous
  • anonymous
Science disproves magic, thus it can't "disappear" :)
anonymous
  • anonymous
give the 1st derivative a shot, help_with_math
anonymous
  • anonymous
Is the first derivative 1/2cos (t) - 2sin(2t)
anonymous
  • anonymous
right
anonymous
  • anonymous
cool so what do we do next
anonymous
  • anonymous
Second derivative
anonymous
  • anonymous
2nd der = -1/2sin(t) -4cos (2t)
anonymous
  • anonymous
yes
anonymous
  • anonymous
i think im gettin the hang of teh chain rule
anonymous
  • anonymous
so after finding teh sec derivative do we just substitute pi/2
anonymous
  • anonymous
yes
anonymous
  • anonymous
i got 7/2
anonymous
  • anonymous
thats the answer
anonymous
  • anonymous
.im sorry that in this point in calc im still confused about sum things. But it doesnt take long 2 learn it i guess. THANKS AGAIN =)
anonymous
  • anonymous
yw

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