find the inverse of f(x) = x^5 + 2x^3 + x - 1

- anonymous

find the inverse of f(x) = x^5 + 2x^3 + x - 1

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- anonymous

mah man!

- anonymous

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- anonymous

well the question is find g'(-1) where g is the inverse of f

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## More answers

- anonymous

i don't think that form is of any use to me

- anonymous

g'(x) = 1 / (f'(g(x))

- anonymous

take the derivative and solve for dy/dx

- anonymous

OHHHHHHHHH

- anonymous

<3

- anonymous

lol

- anonymous

sob, i wish i had math vision like you

- anonymous

rusty here ...

- anonymous

who are you anyway, teacher?

- anonymous

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- anonymous

not done yet ...

- anonymous

find y in the main equation when x = -1

- anonymous

did you get the right answer?

- anonymous

did you ask me if I'm a teacher ?

- anonymous

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- anonymous

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- anonymous

as long as you keep the cross product the same the expressions are quivalent

- anonymous

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- anonymous

i never seen just "dx" alone used like that before, didn't know you could do that

- anonymous

dx is the derivative of x

- anonymous

I know this method is easier than the one you have ...

- anonymous

have you ever read Calculus made easy by Thompson ?

- anonymous

http://www.gutenberg.org/ebooks/33283

- anonymous

nope

- anonymous

i'm confused, why did we take the derivative of that again?

- anonymous

read it ! you'll see methods that are hidden from students !

- anonymous

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- anonymous

Ok ...where are you confused ?

- anonymous

I just did it once !

- anonymous

I'll write the steps down

- anonymous

f(x) = x^5 + 2x^3 + x - 1, find the inverse derivative (g'(b)) b = -1

- anonymous

the answer is 1 says my textbook

- anonymous

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- anonymous

yes .... x is y in the inverse ... darn

- anonymous

if g is the inverse of f, then g' = dy/dx = 1/5y^4 + 6y^2 + 1 right?

- anonymous

yes

- anonymous

then g'(-1) = 1 / 5(-1)^4 + 6(-1)^2 + 1?

- anonymous

yes

- anonymous

what is the answer in your book?

- anonymous

1

- anonymous

hmmm

- anonymous

yeah i don't know, this question isn't even important for class

- anonymous

hold on ....it shouldn't be this hard !

- anonymous

i'll type out the entire question, maybe i asked it wrong..

- anonymous

show point (a,b) lies on graph of f
f(x) = x^5 + 2x^3 + x - 1 ; (0,-1)
find g'(b) where g = inverse of f

- anonymous

don't worry about it, it's a dumb question and not even gonna be on the exam

- anonymous

i'm about to pass out x_x

- anonymous

oh, and yeah, are you a teacher or something? masters in math or something

- anonymous

you know ...I'll solve it and send it to you ...

- anonymous

with both methods

- anonymous

hahah that'd be nice

- anonymous

should go help someone else though, reallocate your skills

- anonymous

gotta sleep, i'll see you around mathg8

- anonymous

the slope of the inverse function at (c,d) is the reciprocal of the slope of the original function at (d,c)

- anonymous

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- nikvist

\[g(f(x))=x\quad\Rightarrow\quad g'(f(x))f'(x)=1\]\[g'(f(0))f'(0)=1\]\[g'(-1)f'(0)=1\]\[g'(-1)=1/f'(0)=1\]

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