anonymous
  • anonymous
find the inverse of f(x) = x^5 + 2x^3 + x - 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
mah man!
anonymous
  • anonymous
|dw:1333425042398:dw|
anonymous
  • anonymous
well the question is find g'(-1) where g is the inverse of f

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More answers

anonymous
  • anonymous
i don't think that form is of any use to me
anonymous
  • anonymous
g'(x) = 1 / (f'(g(x))
anonymous
  • anonymous
take the derivative and solve for dy/dx
anonymous
  • anonymous
OHHHHHHHHH
anonymous
  • anonymous
<3
anonymous
  • anonymous
lol
anonymous
  • anonymous
sob, i wish i had math vision like you
anonymous
  • anonymous
rusty here ...
anonymous
  • anonymous
who are you anyway, teacher?
anonymous
  • anonymous
|dw:1333425303185:dw|
anonymous
  • anonymous
not done yet ...
anonymous
  • anonymous
find y in the main equation when x = -1
anonymous
  • anonymous
did you get the right answer?
anonymous
  • anonymous
did you ask me if I'm a teacher ?
anonymous
  • anonymous
|dw:1333425793857:dw|
anonymous
  • anonymous
|dw:1333425920193:dw|
anonymous
  • anonymous
as long as you keep the cross product the same the expressions are quivalent
anonymous
  • anonymous
|dw:1333426053065:dw|
anonymous
  • anonymous
i never seen just "dx" alone used like that before, didn't know you could do that
anonymous
  • anonymous
dx is the derivative of x
anonymous
  • anonymous
I know this method is easier than the one you have ...
anonymous
  • anonymous
have you ever read Calculus made easy by Thompson ?
anonymous
  • anonymous
http://www.gutenberg.org/ebooks/33283
anonymous
  • anonymous
nope
anonymous
  • anonymous
i'm confused, why did we take the derivative of that again?
anonymous
  • anonymous
read it ! you'll see methods that are hidden from students !
anonymous
  • anonymous
|dw:1333426463640:dw|
anonymous
  • anonymous
Ok ...where are you confused ?
anonymous
  • anonymous
I just did it once !
anonymous
  • anonymous
I'll write the steps down
anonymous
  • anonymous
f(x) = x^5 + 2x^3 + x - 1, find the inverse derivative (g'(b)) b = -1
anonymous
  • anonymous
the answer is 1 says my textbook
anonymous
  • anonymous
|dw:1333426756789:dw|
anonymous
  • anonymous
yes .... x is y in the inverse ... darn
anonymous
  • anonymous
if g is the inverse of f, then g' = dy/dx = 1/5y^4 + 6y^2 + 1 right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
then g'(-1) = 1 / 5(-1)^4 + 6(-1)^2 + 1?
anonymous
  • anonymous
yes
anonymous
  • anonymous
what is the answer in your book?
anonymous
  • anonymous
1
anonymous
  • anonymous
hmmm
anonymous
  • anonymous
yeah i don't know, this question isn't even important for class
anonymous
  • anonymous
hold on ....it shouldn't be this hard !
anonymous
  • anonymous
i'll type out the entire question, maybe i asked it wrong..
anonymous
  • anonymous
show point (a,b) lies on graph of f f(x) = x^5 + 2x^3 + x - 1 ; (0,-1) find g'(b) where g = inverse of f
anonymous
  • anonymous
don't worry about it, it's a dumb question and not even gonna be on the exam
anonymous
  • anonymous
i'm about to pass out x_x
anonymous
  • anonymous
oh, and yeah, are you a teacher or something? masters in math or something
anonymous
  • anonymous
you know ...I'll solve it and send it to you ...
anonymous
  • anonymous
with both methods
anonymous
  • anonymous
hahah that'd be nice
anonymous
  • anonymous
should go help someone else though, reallocate your skills
anonymous
  • anonymous
gotta sleep, i'll see you around mathg8
anonymous
  • anonymous
the slope of the inverse function at (c,d) is the reciprocal of the slope of the original function at (d,c)
anonymous
  • anonymous
|dw:1333428128766:dw|
nikvist
  • nikvist
\[g(f(x))=x\quad\Rightarrow\quad g'(f(x))f'(x)=1\]\[g'(f(0))f'(0)=1\]\[g'(-1)f'(0)=1\]\[g'(-1)=1/f'(0)=1\]

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