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bobobobobb

  • 4 years ago

lim tan3x/ 3tan2x x->0

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  1. brainshot3
    • 4 years ago
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    Is it zero? Separate the two and multiply out. It is either zero or indeterminate, but I'd go with zero.

  2. liliy
    • 4 years ago
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    0.

  3. bobobobobb
    • 4 years ago
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    the answerr is 1/2

  4. yash007
    • 4 years ago
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    use l' hospital rule and u'll get 1/2

  5. brainshot3
    • 4 years ago
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    Just checked it on Wolfram Alpha. The answer is 0.

  6. vi3tbloodxx
    • 4 years ago
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    Using the l'Hôpital's rule: Take derivative of the top and the bottom: tan3x = 3sec²3x 3tan2x = 6sec²2x So its: 3sec²3x/6sec²2x Now plug in x=0 You'll get 3(1)/6(1) = 3/6 =1/2

  7. bobobobobb
    • 4 years ago
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    Thanks all for your help. Any solution without that rule for now? Because the teacher said that we should be able to do this question without any rules. I wasnt taught l'hopitals rule yet

  8. yash007
    • 4 years ago
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    then using trigonometic formulaes u can xpand it and then u'll get what u want...:) all d best..:)

  9. liliy
    • 4 years ago
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    @bobobobobb so then i'm gonna have to say, go with zero

  10. brainshot3
    • 4 years ago
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    It would be zero. Divide and conquer; veni vidi vici. Tan... * tan... will both go to zero, multiply out and you will get zero.

  11. yash007
    • 4 years ago
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    no i just solved it with trigonometric formulaes i'm getting 1/2

  12. bobobobobb
    • 4 years ago
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    the answer key says 1/2 but i dont know how

  13. yash007
    • 4 years ago
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    see in numerator u xpand tan 3x and do the same for 6tan 2x in denominator and then put x=0 and u'll get 1/2

  14. bobobobobb
    • 4 years ago
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    expand? what does that mean?

  15. yash007
    • 4 years ago
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    means apply formula for tan 3x and u'll get everything in tan x same u do in denominator and then put x=0 to get ur result

  16. bobobobobb
    • 4 years ago
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    okay. thank you very much

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