having trouble getting started on hydrostatic pressure in calc II. I thought I had it down in class, but I am getting none of the answers right, so I must be forgetting some step.
we have a shape
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where the top triangle is 1m tall and wide, the bottom rectangle portion is 1m wide and 2m tall, the whole surface is suspended vertically in a liquid with mass density of 500kg/m^3. the topmost corner of the triangle portion is at the point of the surface. Calculate the force in
newtons on the surface.
I tried integrate(500*9.8*y^2dy) from 0 to 1 plus integrate(500*9.8*ydy) from

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|dw:1333427330281:dw|

i assume the bottom is easy enough to calculate

\[\int_{0}^{1}\int_{1}^{3}500\ dd.dw\]

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