• anonymous
A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30ft above the ground. The lantern start to fall, thus causing the person shadow to lengthen(L). Given that the lantern falls 16t^2 ft in t seconds, how fast will the shadow be lengthening when t=1 * l l 30ft l 6ft s= the height f the falling lantern l___10ft__l__L___ I got S/(x+10)=6/x solved for s=(6x+60)/x put that in for -16t^2+30=s found the x value for when the height has come down for a second (30-16) and got 7.5. took the derivative in respect to t -32t=6x(-60/x^2)(dx/dt) d
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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