anonymous
  • anonymous
In the voltaic cell with a porous pot, first the zinc rod release electron and become zinc ion dissolve into the solution. Then the electron flow to the copper rod through the external circuit, the electron is then discharge the copper ion in the copper sulphate solution. I hope the statement above is right. But now, what will happen to the excess zinc ion in the zinc sulphate solution and the sulphate ion in the copper sulphate solution?
Chemistry
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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JFraser
  • JFraser
the concentration of zinc ions in the pot increases, while the concentration of the copper ions decreases as copper is plated onto the copper electrode. The sulfate ions migrate through the pot from outside (where the Cu+2 concentration is decreasing) to inside (where the Zn+2 concentration is increasing) in order to maintain charge balance.
anonymous
  • anonymous
So only sulphate ion can move in and out of porous pot while Zn and Cu ion can't? IS it because of their molecular size?

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JFraser
  • JFraser
the copper ions won't move into the pot because they're being plated onto the copper electrode. the zinc ions might move through the pot, but its more likely that the sulfate ions will move in as the copper ions are removed, so the charge balance is maintained

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