anonymous
  • anonymous
At a certain rate of simple interest, a certain sum doubles itself in 10 years. In how many years will it triple itself?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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lgbasallote
  • lgbasallote
15 years?
anonymous
  • anonymous
How??
anonymous
  • anonymous
I think your answer is correct lgbasallote, because 15 is one of the options.

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More answers

lgbasallote
  • lgbasallote
what i did was it doubles in 10 years...so it quadruples in 20...in between is 150 -> triple
lgbasallote
  • lgbasallote
15*
anonymous
  • anonymous
I there no other way?
anonymous
  • anonymous
*Is
lgbasallote
  • lgbasallote
i dont know...seems there is an algebraic equation for it..but i cant equate it..
anonymous
  • anonymous
Can we take the rate as a constant(say, 5%) and the principal as x?
lgbasallote
  • lgbasallote
ratio and proportion can be used too i guess 2:10 = 3:x 30 = 2x x = 15
anonymous
  • anonymous
@amistre64 can you help?
experimentX
  • experimentX
ln(2) = 10 ln(1+ r/100) => rate must be 7.17735 ln(3) = x ln(1+ 7.17735/100) => x = 15.8496 http://www.wolframalpha.com/input/?i=solve+ln%283%29+%3D+x+ln%281%2B+7.17735%2F100%29
anonymous
  • anonymous
But its not compound interest, its simple interest.
anonymous
  • anonymous
What is In?
experimentX
  • experimentX
I = PTR/100 => I = P => R => 100/10 for tripling 2I = PTR/100 => T=15
anonymous
  • anonymous
How is I = P(in the second step)??
experimentX
  • experimentX
for sum to double .. . you need Interest = Principal => I+P = A = 2P and same logic goes for tripling
anonymous
  • anonymous
Oh, I see... thanks.
anonymous
  • anonymous
Sorry to trouble you but how is R = 100/10.
anonymous
  • anonymous
@experimentX
experimentX
  • experimentX
I and R cancel out I = PTR/100 =>1 = TR/100 => T = 10 => 1 = R10/100 => R = 100/10
anonymous
  • anonymous
Thanks.

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