anonymous
  • anonymous
Three married couples arrange a party. They arrive at the party one at a time, the couples not necessarily arriving together. They all, upon arriving, shake the hand of everyone already there, except their own spouse. When everyone has arrived, someone asks all the others how many hands they shook upon arriving, and gets five different answers. How many hands did he himself shake upon arriving?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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experimentX
  • experimentX
?? five different answers ??
anonymous
  • anonymous
5 ?
anonymous
  • anonymous
five..

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More answers

anonymous
  • anonymous
The answer is he shook 2 people's hands.
anonymous
  • anonymous
how?
anonymous
  • anonymous
@FoolFor, how could u get the answer?
experimentX
  • experimentX
must be six .. because there are 3 couples .. and this seventh person is an outsider
anonymous
  • anonymous
This is a very old combinatoric puzzle.
experimentX
  • experimentX
but i there were 3 couples and they shook each other hand .. except of their own spouse ... they they must have shaken hand 4 times ... each of them ...but why 5 different answers would come??
experimentX
  • experimentX
@JoshDavoll if the person was insider .. then answer must be 4
apoorvk
  • apoorvk
he asked 5 people means including him, there were 6. that means he was the last to arrive. so, he shook 4. he didnt shake his own hands definitely, and definitely not with his spouse.
anonymous
  • anonymous
the answer is 2
apoorvk
  • apoorvk
yeah, if he was the insider as you say.
anonymous
  • anonymous
i have a solution, gimme a sec
inkyvoyd
  • inkyvoyd
@FoolForMath is probably correct.
anonymous
  • anonymous
http://www.gottfriedville.net/mathprob/misc-shakes2.html
anonymous
  • anonymous
he asked them after all this happened, i think you misunderstand
anonymous
  • anonymous
number the couples 1 , 2 , 3
anonymous
  • anonymous
so m1 is male from couple 1 , and f1 is female from couple 1
anonymous
  • anonymous
etc etc
experimentX
  • experimentX
if he asked without shaking hand .. and the pair couple shook hand 3 times while the unpaired couple shook 4 times
anonymous
  • anonymous
first to arrive is m1, he shakes 0 peoples hands second is m2 he shakes 1 third is m3 he shakes 2 fourth is f1 she also shakes 2 fifth is f2 she shakes 3 sixth is f3 she shakes 4 the asker is either m3 or f1 , and they get 5 different answers
anonymous
  • anonymous
Ah i get it now, thanks for explaining it :)
experimentX
  • experimentX
how many hands ON ARRIVING?? i think i understood the question now.
anonymous
  • anonymous
of course we haven't checked thats the only solution, but you can change around the numbers to get a solution that looks different but is the same

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