- anonymous

The magnification of a magnifying lens of focal length 5 cm is :(final image is at infinity)
a) 1
b) 2
c) 3
d) 5

- chestercat

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- anonymous

wat si the type of lens that magnifies ur imge and also produces a virtual image?
answer this question
then wat is the ray diagram for getting image at infinity with that type of lens?
wat is lens formula relating f,u,v
i can get my v from that?
wat is magnification? in terms of u and v
u are near the answer once u have ansered all these questions

- anonymous

The lens must be a convex lens. The object is at focus.

- anonymous

\[1/v - 1/u = 1/f\]

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## More answers

- anonymous

Here, v = 0

- anonymous

Also, m = v/u

- anonymous

But, I am not getting the answer.

- anonymous

put down the ray diagram for me when image is at infinity for convex lens

- anonymous

Just one minute. Here is the diagram.

- anonymous

|dw:1333555806014:dw|

- anonymous

@salini didi, Now say what to do.

- anonymous

yeah so? u=?

- anonymous

object disatnce=?

- anonymous

u = 5

- anonymous

then? tell me how do i proceed?

- anonymous

m = f/(f+u) = 5/(5+5) = 0.5?????

- anonymous

m=v/u u never used taht?

- anonymous

But how to do? Please say in detail the complete steps.

- anonymous

u know that formula?

- anonymous

U say akka. PLease.

- anonymous

i forgot for lenses tahts y ia m asking u

- anonymous

Ohhhhhhh!!! Can u please post the details tomorrow? I have to go now. Bye.

- anonymous

ok bye! see pg.182 of 10th ncert text book

- anonymous

Okay, will look and say tomorrow.

- anonymous

Its given that, m = v/u = h1 / h2

- anonymous

yeah so u know u, find V using lens formula then apply u/v to find magnification(the extent to which the image is magnified w.e.to object)
the key here is taht u=focal length that u will come to know ONLY WHEN U DRAW THE RAY DIAGRAM!

- anonymous

But, v = 0 na?

- anonymous

1/f=1v-1/u
1/v=1/f+1/u
by sign convention
f=-5
u=-5

- anonymous

@salini didi, then,
m = f/(f+u) = 5[5 + (-5)] = 5/0?????

- anonymous

v=?

- anonymous

v = 0, rite?

- anonymous

U learnt ssign convention?>

- anonymous

yeah. U try and see. This problem uses some different formula. Then only we can get it.

- anonymous

i will get back to you later after searching abt this problem

- anonymous

OK.

- anonymous

http://in.answers.yahoo.com/question/index;_ylt=AkFa8X1nxFG0SZ3pw3unEkYazKIX;_ylv=3?qid=20120406084524AArIAkz

- anonymous

- anonymous

U r correct didi!!!!!! Cheers!!!!!!! thanks for the solution.

- anonymous

:) we learn nothing...........there is so much to learn further

- anonymous

Oooooooooo. But, it is a continous process. Being happy is also a continuous process. So, be happy!!!!!!:P

- anonymous

!!!!!!!!!!!!!!!!!! i dont know wat to type
:)

- anonymous

Hehehehheheheheh!!!!!!!!!! Crazy Sister!!!!!!!!!!!!!

- anonymous

Can't stop laughing!!!!!!!!!!!!!!!!!!!!

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