If f(x) is divisible by 2x+3, then f(x+1) is divisible by?
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2x + 5? hehe just guessing
i forgot, I just suddenly remember this type of question and I cannot solve it..
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2(x+1) + 3 ?
From the given information,
f(x) = (2x+3) Q(x) so, f(x+1) = (2x+5) Q(x+1)
So, Ishaan is right.
Yeah Ishaan, I would have guessed the same.
Alright , i don't understand.
What about if f(x) is divisible by x-1, which of the following must be a factor of f(2x+1) ?
B . x-3
This time.. I've got the answer for this one , but i don't know how to solve it
Let \( f (x) = (x - 1) Q (x)\), then \[ f (2x + 1) = (2x + 1 - 1) Q (2x + 1)= 2x Q (2x + 1) \]
Hence x is a factor of f (2x + 1).
Oh this time i understand, thanks!!!
I am glad you did.
Time for the problem of the day guys! ;)
right, for the first one i don't understand
f(x) = (2x+3) Q(x)
f(x+1) = (2x+3 +1) Q(x+1) = 2(x+1) Q(x+1) ?
When you find f(x+1), you just substitute x+1 instead of x. No other changes in that. Just like to find f(2) you substitute 2 instead of x.