anonymous
  • anonymous
radical expression simplfy
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\sqrt{14q}* 2\sqrt{4q}\]
lgbasallote
  • lgbasallote
factor out sqrt (14q) and sqrt (4q) individually first. im sure youll get some idea after
anonymous
  • anonymous
any factors

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lgbasallote
  • lgbasallote
hmmm let's start with sqrt (4q)...it's equal to sqrt (4) times sqrt (q) what do you notice?
anonymous
  • anonymous
2 and 2
lgbasallote
  • lgbasallote
hmm good observation..so it's 2^2 right? sqrt (2^2) = 2 yes? so it's sqrt (14q) + 2(2)(sqrt q) you can factor out sqrt q here... sqrt q (sqrt 14 + 4)
anonymous
  • anonymous
@lgbasallote 4q sqrt14q
anonymous
  • anonymous
sqrt14 w/o q
lgbasallote
  • lgbasallote
oh wait it's multiplication o.O
anonymous
  • anonymous
so is it 3 sqrt56q^2
anonymous
  • anonymous
or is it a 2
lgbasallote
  • lgbasallote
lemme repeat that 2 (sqrt 4q) = 4 sq (q) 4 sq (q) times sqrt 14 q = 4 sqrt (14q^2) = 4q sqrt 14
anonymous
  • anonymous
can u simplify sqrt 144 i put 12 it was wrong
lgbasallote
  • lgbasallote
sqrt 144 = 12
anonymous
  • anonymous
\[-2 \sqrt{2p}*2\sqrt{22}\]
anonymous
  • anonymous
Whats this
phi
  • phi
Starting with \[ \sqrt{144q}\cdot 2\sqrt{4q} \] Look for perfect squares (if you know your times table up to 12 times 12, then you know 12^2 = 144 and 2^2= 4) Take the square root of the perfect squares. We get \[ 12\cdot 2 \cdot 2\cdot \sqrt{q}\cdot \sqrt{q} \] Of course \( \sqrt{q} \cdot \sqrt{q} = q \) and the simplified expression is 48q
anonymous
  • anonymous
where u get 144 that was another question
anonymous
  • anonymous
@phi where u get 144 that was another question
phi
  • phi
If the problem is \[ \sqrt{14q}\cdot 2\sqrt{4q} \] then you get \[ 2\cdot 2 \cdot \sqrt{14}\cdot \sqrt{q}\cdot \sqrt{q} \] which simplifies to \[ 4q\sqrt{14} \]

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