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Starshine7

  • 2 years ago

Cyclist rode first 36 mile portion of his race at constant speed. For 27 cooldown portion he reduced his speed by 3 miles per hour. Each portion took same time, find cyclist speed during first portion and speed during cooldown. Show me how to set it up? Thanks.

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  1. King
    • 2 years ago
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    let constant speed be v then, t=36/v fr 1st portion

  2. Starshine7
    • 2 years ago
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    36/x-3=27/x-3 Is this right?

  3. King
    • 2 years ago
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    fr 2nd portion let speed be v/3 so, t=27/(v-3)

  4. King
    • 2 years ago
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    no its 36/x=27/x-3

  5. Starshine7
    • 2 years ago
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    |dw:1333458593743:dw|

  6. perl
    • 2 years ago
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    king, maaf keejie

  7. Starshine7
    • 2 years ago
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    did i set it up right?

  8. perl
    • 2 years ago
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    king, meri samajh mei nahin aaya

  9. King
    • 2 years ago
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    kya samaj nahi aara...@Starshine7 yeah its rite

  10. Starshine7
    • 2 years ago
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    thank you :)

  11. perl
    • 2 years ago
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    king, calculus

  12. King
    • 2 years ago
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    so nw equate and tell me what value u get fr v?

  13. King
    • 2 years ago
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    so what do i do?

  14. Starshine7
    • 2 years ago
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    ok just a sec. :)

  15. perl
    • 2 years ago
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    i will post it,

  16. perl
    • 2 years ago
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    king, thanks

  17. perl
    • 2 years ago
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    mine english not good

  18. Starshine7
    • 2 years ago
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    12?

  19. King
    • 2 years ago
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    yup awesome!!

  20. Starshine7
    • 2 years ago
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    Great! Thanks so much for the help! :3

  21. King
    • 2 years ago
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    ure welcome!! :D:D:D:D

  22. Starshine7
    • 2 years ago
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    :D

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