anonymous
  • anonymous
Cyclist rode first 36 mile portion of his race at constant speed. For 27 cooldown portion he reduced his speed by 3 miles per hour. Each portion took same time, find cyclist speed during first portion and speed during cooldown. Show me how to set it up? Thanks.
Mathematics
jamiebookeater
  • jamiebookeater
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King
  • King
let constant speed be v then, t=36/v fr 1st portion
anonymous
  • anonymous
36/x-3=27/x-3 Is this right?
King
  • King
fr 2nd portion let speed be v/3 so, t=27/(v-3)

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King
  • King
no its 36/x=27/x-3
anonymous
  • anonymous
|dw:1333458593743:dw|
perl
  • perl
king, maaf keejie
anonymous
  • anonymous
did i set it up right?
perl
  • perl
king, meri samajh mei nahin aaya
King
  • King
kya samaj nahi aara...@Starshine7 yeah its rite
anonymous
  • anonymous
thank you :)
perl
  • perl
king, calculus
King
  • King
so nw equate and tell me what value u get fr v?
King
  • King
so what do i do?
anonymous
  • anonymous
ok just a sec. :)
perl
  • perl
i will post it,
perl
  • perl
king, thanks
perl
  • perl
mine english not good
anonymous
  • anonymous
12?
King
  • King
yup awesome!!
anonymous
  • anonymous
Great! Thanks so much for the help! :3
King
  • King
ure welcome!! :D:D:D:D
anonymous
  • anonymous
:D

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