• anonymous
a rocket is launched vertically from a point on level ground that is 3000 feet from the observer with binoculars. if the rocket is rising vertically at the rate of 750 ft/s at the instant it is 4000 above the ground, how fast must the observer change the angle of elevation of her line of sight in order to keep the rocket in sight at that instant? did theta= (1/(1+(x/3000)^2)(dx/dt) exactly like the formula for tan(theta) x/y instructs you to. I get .1405 when I rationalize and when I don't 270 for d(theta)/dt Niether of which is the correct answer.
Mathematics
• Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Looking for something else?

Not the answer you are looking for? Search for more explanations.