Hi everyone, I was wondering if someone could check my assessment for me. All of the answers are logged in, I just need someone to check them and tell me if they're right or wrong.

- LifeIsADangerousGame

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- anonymous

welcome

- LifeIsADangerousGame

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- anonymous

2 is false.

- anonymous

1 is correct :D

- anonymous

I'm guessing there's an option D for assignment 2?

- LifeIsADangerousGame

Yes, that's in the assessment 2 (continued) attachment

- anonymous

D is the correct ans for 2

- anonymous

Thomas is right :D

- anonymous

Notice how you get g(x)=0 for x=-3

- LifeIsADangerousGame

Wait, I'm confused, how do I get the answer for number 2?

- anonymous

@thomas9, I think you would like to explain a bit more in order to help. I'll leave it to you as you find this mistake :D

- anonymous

Ok, first off: |x+3| is always positive, so it's not B or C, right?

- LifeIsADangerousGame

Right

- anonymous

From the graph in A you can see that g(x)=0 for x=3, but |3+3|=6 =/= 0, So it's not A either.

- anonymous

Which leaves D, furthermore from D we find g(x)=0 for x=-3, which is true: |-3+3|=0.

- anonymous

(g(x) is y in this case)

- LifeIsADangerousGame

Don't we want a positive number and not 0?

- anonymous

0 is positive in my opinion, |x+3| is not negative if you like that better.

- anonymous

So is it clear?

- LifeIsADangerousGame

Well yea, but how is the answer A not negative? They both have arrows going into the negative quarter

- anonymous

The vertical axis denotes |x+3|, if |x+3| were negative it would be in the lower half of the graph. With option A it just goes in the left half which means x becomes negative, but not |x+3|.

- anonymous

|dw:1333466168559:dw|

- LifeIsADangerousGame

Ohhh

- LifeIsADangerousGame

I see!

- LifeIsADangerousGame

(I need the rest of the answers checked)

- anonymous

5 and 8 are wrong and I'm uncertain about 7 and 12. The rest is correct.

- Callisto

1. correct
2.incorrect
3. correct
4. correct
5. incorrect
6. Dunno
7. correct
8. incorrect
9. Dunno
10. correct
11. correct
12. correct

- Callisto

For 5, the one you've selected is a quadratic one, not a linear one. Linear equation should have a form like y=mx+c (c could be 0)

- anonymous

9. D) is correct since it's the only one where there isn't more than one value for a given x

- Callisto

For 8, you should check the y-int first,
y-int is = 4
So, put x=0 into the equations, (b) would be rejected immediate;y
and then check the x -int
put y=0 into the equations, (a) and (d) will also be rejected.
So the only option left is the answer

- Callisto

*immediately

- LifeIsADangerousGame

So five should be B?

- LifeIsADangerousGame

and 8 is C?

- Callisto

8 correct
5 wrong, for direct variation, the y-int is 0, so c=0 in y=mx+c

- LifeIsADangerousGame

It's y = mx + c but there isn't any equation with two numbers multiplying each other plus another number :/

- anonymous

don't forget that x+2 = 1x+2. Even if you don't see the "1", it's still there

- LifeIsADangerousGame

So then f(x) = l x + 2 l is correct?

- Callisto

You mean question 5?

- LifeIsADangerousGame

Yes question 5 sorry

- LifeIsADangerousGame

But if what charron said is right, wouldn't that mean that x + 2 is correct since even if I don't see the one it's still there: x + 2 = 1x + 2?

- anonymous

yes, for question 5, since you're looking for a linear equation (owhich the form is y = mx+c, has you've stated), x+2 is definitely it. Also, please note that, if you had y =4, that would be a linear equation as well with m = 0 (y= 0x + c)

- LifeIsADangerousGame

Ohh ok, thanks :)

- LifeIsADangerousGame

Thank you everyone! I got 100%!!

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