anonymous
  • anonymous
evaluate lim x --> infinity of function (e ^ -x) ln x using l'hopitals rule Thanks to anyone who gives it a shot
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\LARGE \lim_{x\to \infty}e^{-x}\cdot \ln x\] is this what you mean ?
anonymous
  • anonymous
yes that is correct
anonymous
  • anonymous
\[\LARGE (u\cdot v)'=u'\cdot v+u\cdot v'\] you're supposed to know this rule... do you know it ?

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anonymous
  • anonymous
absolutely..but hopitals rule doesnt apply it..at least i didnt think it did
anonymous
  • anonymous
...now you got me confused to.. O_O , is L'Hopital's Rule about derivatives when you're \[\LARGE \frac{\infty}{\infty} \quad \quad , \quad \quad \frac00\] ... ? :(
experimentX
  • experimentX
0
anonymous
  • anonymous
@experimentX yeah I know it's 0 .. http://www.wolframalpha.com/input/?i=lim_%7Bx%5Cto+%5Cinfty%7De%5E%28-x%29*ln+x but how to do it !! ??
experimentX
  • experimentX
put that e^x on down and use L'hospital rue
anonymous
  • anonymous
i got that far experiment..but then i get (1/x)/(e^x) after taking the derivative...at that point im stuck
experimentX
  • experimentX
now .. as x-> inf your function = 1/inf = 0
anonymous
  • anonymous
doesnt numerator go to 0 and denom to inf? (1/x --> 0 with x --> inf)
experimentX
  • experimentX
yeah .. so it is your limit ...better than inf/inf isn't it??
anonymous
  • anonymous
use drawing.. you can understand each other better !
experimentX
  • experimentX
yeah .. just click on the link posted by @Kreshnik
anonymous
  • anonymous
alright thanks alot..didnt see the link..take care
experimentX
  • experimentX
oops sorry there wasn't graph!

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