anonymous
  • anonymous
In a single-slit diffraction pattern, the distance between the first and second minima is 1.8cm on a screen 4.4m from the slit. Find the slit width given that the wavelength of the light is 550nm.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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ash2326
  • ash2326
@Mythias it won't help much posting this here. Please post this in Physics. Thanks:)
anonymous
  • anonymous
its just that the physics forum is dead....lol plus ive always gotten more help here LOL
Callisto
  • Callisto
First, you should put this question in the Physics group. Second, slit width = λD/a , if you remember it correctly

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More answers

Callisto
  • Callisto
sorry , you -> I :S
experimentX
  • experimentX
seems like double slit interference
Callisto
  • Callisto
that would be dsinθ = mλ, i believe
anonymous
  • anonymous
ya the formulas u guys have r correct
experimentX
  • experimentX
that looks like bragg's law ... if you add 2 on lhs ...
anonymous
  • anonymous
do we do y=mlamdaL/d?
Callisto
  • Callisto
sorry i remember that wrong :S fringe separation = λD/a, a is the slit separation, d is the distance from the screen ...
Callisto
  • Callisto
1.8/100 = ( 550x10^-9 ) (4.4) /a a = ( 550x10^-9 ) (4.4) / 0.018
experimentX
  • experimentX
yeah you are right .. same as iterference comes form here http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/imgpho/ymin2.gif
Callisto
  • Callisto
I don't like doing these king of question, i mixed the formulas up or can't remember the unknowns well :S
Callisto
  • Callisto
*kind
anonymous
  • anonymous
thanks guys :)

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