anonymous
  • anonymous
Estimate the acceleration due to gravity at the surface of Europa(one of the moons of Jupiter)given that its mass is 4.9 * 10^22kg and making the assumption that its density is the same as Earth's.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I know I have to use this equation: \[g=Gm _{E}/r^2 where m _{E} is Europa\]
anonymous
  • anonymous
So I get this: \[(6.67*10^-11kg)(4.9*10^22)/(6.389*10^6m)^2=.08m/s^2 \] is this right?
anonymous
  • anonymous
yes that is correct :) glad u got it

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
If thats the case then when I try plugging this into my computer its saying the answer is wrong. The exact answer on my calculator reads: .0800674759. It says use 2 sig figures in my answer so would it be 8.0*10^-2?
mos1635
  • mos1635
the radius you are using is wrong. 6,389*10^6 is the radius of earth note your text, it says densidy og earth!!!! use m=d*V m=d* 4/3*π*r^3 once for moon, once for earth to find radius of moon...
anonymous
  • anonymous
okay i'll use that and see what I get. Thanks.
anonymous
  • anonymous
The density for the earth is: \[V_{e}=4/3\pi(6.389*10^6m)^3=1.09*10^{21}\] \[D_{e}=5.98*10^24kg/1.09*10^{21}=5.48*10^{45}\]
mos1635
  • mos1635
10^24/10^21=10^3 !!!!!
mos1635
  • mos1635
but there is no need to calculate the De 1 for earth 2 for moon M1=d*4/3*pi*R1^3 M2=d*4/3*pi*R2^3 thas M1/M2=(R1/R2)^3 .......R2=
mos1635
  • mos1635
need to go hope you got it
anonymous
  • anonymous
ok i'll try that then.
anonymous
  • anonymous
Now I get .75m/s^2 but it says its wrong.
mos1635
  • mos1635
let me do the calculations and i will get back to you....
mos1635
  • mos1635
no time for accuracy my value is 1.9699696....
mos1635
  • mos1635
i will do it again when i have more time
anonymous
  • anonymous
alright. Maybe my radius was off, I got 2.773*10^6(I redid the problem and ended up getting this for a radius) My answer now is 1.178615...m/s^2 but i'll wait until you get back to me before submitting this answer.
mos1635
  • mos1635
i did again same resalt 1.969969...... according to my calculations radius of europa=1,288,045.447 m i am ......pretty sure tham i am right
anonymous
  • anonymous
oh okay, so you were right then, I must of made a mistake somewhere. I'll retry this later and see if I can come up with the answer you got. Thank you.

Looking for something else?

Not the answer you are looking for? Search for more explanations.