Find the values of p so that the function 8sin^3(x)=p-7cos2x would not have any solutions.

Find the values of p so that the function 8sin^3(x)=p-7cos2x would not have any solutions.

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But I've given the answer and it's supposed to be p=(-inf;-15)u(7;inf)

How do you get the 7 to infinity part?

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