anonymous
  • anonymous
A pith ball of mass 9*10^(-5) kg carries a charge of 5 microcoulomb.What must be the charge of another pith ball placed 2 cm above given pith ball such that they are held in equilibrium
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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experimentX
  • experimentX
mg = kq1q2/r^2
anonymous
  • anonymous
Why mg?
anonymous
  • anonymous
isnt it Gm1m2/r^2=kq1q2/r^2

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experimentX
  • experimentX
9*10^(-5)*9.8 = 9x10^9 * 5x10^-6 * q2 /(2x10^-2)^2
experimentX
  • experimentX
5 micro columb is quite huge amount of charge .. if it is in space ... where there is no gravity ... then your formula is correct.
anonymous
  • anonymous
So gravity due to earth is counteracting electrostatic attraction?
experimentX
  • experimentX
|dw:1333489684772:dw|
anonymous
  • anonymous
Oh I think I get it.I have been taking the mass of the other pith ball to be the same and equating those two equations.I see now.Thanx
experimentX
  • experimentX
if this is the case ... on sphere on top of other

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