anonymous
  • anonymous
When do we say that capacitors are connected in series and when do we say that they are connected in parallel?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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experimentX
  • experimentX
|dw:1333490403197:dw|
anonymous
  • anonymous
No I mean what is the condition?
anonymous
  • anonymous
How can you just look at it and say for sure that hey this is series/parallel

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experimentX
  • experimentX
usually we don't get capacitors of desired value ...
anonymous
  • anonymous
Yeah so we couple them to get capacitors of desired value.But while looking at huge circuits I am having problems figuring out which is series or which is parallel
anonymous
  • anonymous
You need to practice, only then you can make out the circuits properly.
anonymous
  • anonymous
So basically there is no definite rule?
anonymous
  • anonymous
There is, but to get better sense you need to practice.
experimentX
  • experimentX
capacitors behave differently for ac and dc ... seriously i hate capacitors.
experimentX
  • experimentX
http://en.wikipedia.org/wiki/Capacitor#Networks
anonymous
  • anonymous
So how do I identify one then
anonymous
  • anonymous
Post one of your circuits. I will see if I can help you.
anonymous
  • anonymous
Just a sec Ill see my book
anonymous
  • anonymous
|dw:1333490968722:dw| Capacitance at each one is 4 microfarad.Need to find net capacitance across AB in microfarad
experimentX
  • experimentX
|dw:1333491155628:dw|
anonymous
  • anonymous
|dw:1333491100452:dw|I'm not sure about your Last capacitor. Current divides itself at every junction.
anonymous
  • anonymous
Or, parallel network
anonymous
  • anonymous
Need to find capacitance
anonymous
  • anonymous
I got the first part.Need help in the second junction
anonymous
  • anonymous
You will need to take q(charge) instead of current. And then apply kirchoff's law in the loop.
experimentX
  • experimentX
|dw:1333491228214:dw|
experimentX
  • experimentX
wow .. Ishaan looks like a real professional.
anonymous
  • anonymous
|dw:1333491397042:dw| In this part which is series or parallel?How
anonymous
  • anonymous
\[\frac QC = V\] Q is for charge, C for Capacitance and V for electric potential. I think you must know about it.
anonymous
  • anonymous
Yeah I do
anonymous
  • anonymous
Look at the experimentx's diagram he explained it.
anonymous
  • anonymous
Didnt get it fully.Just need to know which is series and which is parallel
experimentX
  • experimentX
let's begin at the here |dw:1333491659145:dw|
anonymous
  • anonymous
Ok got that then?
experimentX
  • experimentX
it has an equivalent of half micro farad
anonymous
  • anonymous
No it's 2
experimentX
  • experimentX
i think it's half ... for series.
experimentX
  • experimentX
let's ask ishaan
anonymous
  • anonymous
1/c=1/c1+1/c2
anonymous
  • anonymous
1/c=1/4+1/4=1/2 means c=2 right?
experimentX
  • experimentX
those two at series, would certainly make half micro farad
anonymous
  • anonymous
But why?According to the formula it must be 2
anonymous
  • anonymous
Each one is 4
experimentX
  • experimentX
Oo .. i thought it was each capacitor was 1 micro farad
experimentX
  • experimentX
|dw:1333492025126:dw|
experimentX
  • experimentX
|dw:1333492082845:dw|
anonymous
  • anonymous
Ok got it thanx guys.
experimentX
  • experimentX
|dw:1333492123125:dw|
anonymous
  • anonymous
Total is 8microfarad
experimentX
  • experimentX
oo,, yes ... 2 + 6
anonymous
  • anonymous
|dw:1333492283412:dw| Infinite number of identical capacitors each of capacity 1mF
anonymous
  • anonymous
Need to find equivalent between A and B
anonymous
  • anonymous
Is it 1+1/2+1/4.......
anonymous
  • anonymous
Yes, or just 2
anonymous
  • anonymous
Yeah
experimentX
  • experimentX
i think 1+1/2+1/3+ .... diverges..
anonymous
  • anonymous
How does it go by 1/3
anonymous
  • anonymous
I think it's 4 not 3 experimentx
anonymous
  • anonymous
musn't the next one be 1/4?
experimentX
  • experimentX
oo ,,, didn't see the picture clearly. you are right.
anonymous
  • anonymous
That's all I think.Ill practice more to get the touch of it

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