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calyne
Find the total distance traveled during the first 8s for v = 3t^2 - 24t + 36 -- just tell me what steps i'm supposed to follow to to this, i know the particle is at rest at t = 2,6 and moving in the positive direction when 0=<t<2 and t>6
Velocity is the derivative of distance, so integrate: \[v = 3t ^{2} - 24t + 36\] And input 8 for t.
find \[\int\limits_{0}^{8} (3t^2 - 24t + 36) dt\]