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where is the picture?
I'm assuming we are making the acceleration of gravity as 9.8 right?
did you just want the answer or did you want how to do it?
ok so i do believe that the tension in the string that has a 15 degree angle is 3015 and the tension in the other angle should be 4839.5
those being in newtons of course
Can you explain how you got it? I want to understand to do the problem please.
ok so first you have to set up the free body diagram
i suck at drawing with a mouse to bear with me
then you have to set up your equations for Net force in both the x plane and another for the y plane
in which case the (Fnet)y =T2sin(35) +T1sin(15) - Fg =0
and the (Fnet)x = T2 cos(35) - T1 cos(15) = 0
since both T2 and T1 are unknowns, we solve for either T1 or T2 in the second equation for (fnet)x
i solved for T1
my bad i solved for T2 in the second equation
so T2 = [T1cos(15)]/cos(35)
then you plug in what you got fro T2 into the first equation for (Fnet)y
the rest is just algebra from there
and my bad while i was explaining i realized that i made a mistake in my signs
so let me recalculate it really quick
oh and i believe that to find the kg from the pounds, you need to convert, then multiply by gravity acceleration to get the newtons
ok so after recalculating i found T1 to be 2473N and T2 to be 5084.1N