At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
You can use logarithms... 5ln((x^(3/2)+8)+.5lnx
So I can just log an integral?
I know you can take to log of both sides of an equation (common log or natural log) but log an integral?
I don't recall that from my mathematical days....
You can if you know how to take the int of logarithms, but what I posted isn't the answer, you still have to find the integral of that. I just used logarithms to simplify the problem. If you are taking a class, then the answer may not always be simplified to look as it would if you took the integral of a logarithm as opposed to normally finding the integral. It applies more to differentiation though.
I thought perhaps I would do a u du substitution.
actually that makes more sense
@satellite73 what do you think?
looks good to me wolfram just expanded and integrated term by term but your way looks better
I think what you want to do here is multiply out. You would get Int of x^4/2= Int x^2+8root x. That would be much easier
@brainshot3 not really
X^2 is very easy to integrate and so is 8x^.5.
@satellite73 Can you take the log of a function? (in an integral as suggested by brainshot3) I do not recall doing such a thing. I know you can log both sides of an equation but in an integration...?
Wait, didn't notice the ^5 part.
Thought so. I would never expand anything to the 5th power unless I was force to... too much unnecessary math
But, you are learning this for fun. Don't you want to challenge your self?! =)
There are limits to what I will do. I also, keep the math as correct as possible. I am sure the professor would rather grade the unexpanded version compared to the expanded version. Besides my time is limited.