anonymous
  • anonymous
Find the derivative of the given function. y=3x-2/2x-3
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mimi_x3
  • Mimi_x3
Is it: \[\large \frac{3x-2}{2x-3} \] ?
anonymous
  • anonymous
quotient rule: Lod Hi - Hi d Lo over Lo Lo
anonymous
  • anonymous
Quotient Rule: f'(x) = g(x)f'(x) - f(x)g'(x) / (g(x))²

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Hero
  • Hero
@vi3tbloodxx , don't forget to put proper parentheses to distinguish the numerator: f'(x) = (g(x)f'(x) - f(x)g'(x)) / (g(x))²
anonymous
  • anonymous
what mimi said
anonymous
  • anonymous
yea that's what i meant sorry... ((3x-2)'(2x-3) - (2x-3)'(3x-2)) / (2x-3)² = (3(2x-3)-2(3x-2)) / (2x-3)² = (6x-9-6x+4) / (2x-3)² = -5/(2x-3)²
Mimi_x3
  • Mimi_x3
or.. \[\large y' = \frac{u'v-uv'}{v^{2}} \] u = 3x-2 => u' =3 v = 2x-3 => v'=2
anonymous
  • anonymous
i think i got it: \[3(2x-3)-2(3x-2)/(2x-3)^2\]
anonymous
  • anonymous
is that the same as vi3tbloodxx?
anonymous
  • anonymous
yes with an extra set of parentheses around like this (3(2x-3)-2(3x-2))
anonymous
  • anonymous
oh then thanks just verifying.
anonymous
  • anonymous
You can also use logarithmic differentiation ln(3x-2) - ln(2x-3) = (3/(3x-2)) - (2/(2x-3))

Looking for something else?

Not the answer you are looking for? Search for more explanations.