anonymous
  • anonymous
Suppose 3s represents an even integer. What polynomial represents the product of 3s, the even integer that comes just before 3s, and the even integer that comes just after 3s? A) 27s^3 + 12s B) 27s^3 - 3s C) 27s^3 - 12s D) 3s^3 - 12s
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Directrix
  • Directrix
Even integers differ by two. If 3s is even, the even just below 3s is (3s -2) and the even just above 3s would be (3s+2). Now, just multiply (3s -2) * (3s) * (3s +2) and see what you get. Start with (3s) * (3s -2) and post what that product is.
anonymous
  • anonymous
i dont understand what the s is for and im not really sure what your asking me to do
anonymous
  • anonymous
im also not sure how to put this in my calculator

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Directrix
  • Directrix
s is any integer. Is s = 3, the 2s = 6. If s = 4, the 2s = 8. The idea is to realize that an even number times an odd = even. Those terms won't go in my calculator except for the calculator on my neck, seriously. If 3s is even, then 3s +2 is even, and the same for 3s -2. Evens differ by a multiple of 2.
Directrix
  • Directrix
(3s) (3s -2) ==> the product of these. Just use the distributive property.
anonymous
  • anonymous
9s-6s?
Directrix
  • Directrix
(9s^s -6s)--? 3s times 3s = 3 times 3 times s times s = 9s^2 Multiply these: (9s^s -6s) (3s + 2) and you'll be finished. The first term is NOT 27 s^2. Post here and I'll check.
anonymous
  • anonymous
idk how to this
anonymous
  • anonymous
is it 27^3 - 3s
Directrix
  • Directrix
Yes, you do. It's the (a+b) (c + d) pattern. (9s^s -6s) (3s + 2) Do these and post: 9x^2 times 3s --> 9s^2 times 2 ---> (-6s) times 3s ---> and (-6s) times 2 ----> Write these 4 results here.
anonymous
  • anonymous
i still dont know what im doing idk what the s is for
anonymous
  • anonymous
idk where u got x from too
Directrix
  • Directrix
I don't see any xs so I don't know about them. Forget about s. It's a variable. Your task is to multiply the terms I wrote for you. 9x^2 times 3s --> 9s^2 times 2 ---> (-6s) times 3s ---> and (-6s) times 2 ----> I'll be back to check.
anonymous
  • anonymous
im confused on of your anwers you and and x that isnt supposed to be there and i have no idea how to do your work
anonymous
  • anonymous
im to the point where im about to just guess because this is all really confusing
Directrix
  • Directrix
What confuses me is what you will REFUSE to multiply these: 9x^2 times 3s --> 9s^2 times 2 ---> (-6s) times 3s ---> and (-6s) times 2 ----> Don't worry if what you write is incorrrect. That is not an issue. So, just do it, please.
anonymous
  • anonymous
im not rufussing i dont know how to multiply the numbers you gave me
Directrix
  • Directrix
How did you know how to do this earlier: (3s) (3s -2) = 9s-6s? Of course, it was 9 s^2 - 6s but you were close. So, you know how to multiply. Just do it on those others.
anonymous
  • anonymous
81 243 162 -18 -12 this is what i got idk if its write
Directrix
  • Directrix
Hey, I see what you mean about the x. (3s -2) * (3s) * (3s +2) = (3s)(3s - 2) = 9s^2 - 6s (9s^2 -6s) ((3s + 2) = 27s^3 + 18s^2 + ? + ?? Your task is now the following: (-6s)(3s) = and (-6s)(2) = You do those two and we may be finished. :)
anonymous
  • anonymous
-18 -12
Directrix
  • Directrix
Why is it that you disregard the variables? In Algebra, there will always be variables.
anonymous
  • anonymous
-18s -12s
Directrix
  • Directrix
(3s -2) * (3s) * (3s +2) = (3s)(3s - 2) = 9s^2 - 6s (9s^2 -6s) ((3s + 2) = 27s^3 + 18s^2 + ? + ?? (-6s)(3s) = -18s^2 and (-6s)(2) = -12s --------------------- (3s -2) * (3s) * (3s +2) = 27s^3 - 12s---> Answer
anonymous
  • anonymous
thank you
Directrix
  • Directrix
Glad to help. Learn to multiply those variables.

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