anonymous
  • anonymous
HELP WITH CALCULUS WORD PROBLEM
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The amount of radiation, R(t) in a certain liquid decreases at a rate proportional to the amount the amount present, that is dR/dt= kR, where k is a constant & t is measured in seconds. The initial amount of radiation is 10^6 rads. After 100 secs the radiation has dropped to 10^2 rads.
anonymous
  • anonymous
a) Express R as a function of t b) To the nearest sec, when will the amount of radiation drop below 10 rads? c) What is the half-life of this chemical? That is, how long does it take for the amount of radiation to reach the half life of the original amount?
anonymous
  • anonymous
R(t) = 10^6*e^(kt), where k = (-4ln10)/100 that's part a.

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anonymous
  • anonymous
like how did u get taht value for k
anonymous
  • anonymous
|dw:1333502433447:dw|
anonymous
  • anonymous
|dw:1333502591736:dw|
anonymous
  • anonymous
to get that "C", plug in t=0, R=10^6 still with me so far?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
so now how did u get k
anonymous
  • anonymous
|dw:1333502978443:dw| to get k, all you do is the same thing... plug in values... at t=100, R= 10^2... solve for k.
anonymous
  • anonymous
can sum1 help me with part B AND C
anonymous
  • anonymous
i need help with part B AND C

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