anonymous
  • anonymous
Trig derivatives! Hmm.. can someone explain this to me?
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
So if you want to find dy/dx of sinx+cosy=1, you get cosx/siny = dy/dx. Why?
anonymous
  • anonymous
The part I dont understand is how to isolate dy/dx by the way
anonymous
  • anonymous
Wait! I figured they were both x. You have x and y, so you use partial derivatives or implicit differentiation.

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anonymous
  • anonymous
|dw:1333502757731:dw|
anonymous
  • anonymous
okay thanks guys, but why is it that the y' is on the sin y and not the cos x side?
anonymous
  • anonymous
because you're taking cosy NOT cosx. so you need to use the chain rule: derivative of cosy = -siny * dy/dx
anonymous
  • anonymous
Oh you take the derivative of y only?
anonymous
  • anonymous
Because it is implicit differentiation, so you have to take the derivative with respect to y of x, so you also have to multiply by dy/dx
anonymous
  • anonymous
okay thank you very much

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