anonymous
  • anonymous
Differential equations: x''+2x'+2x=2*delta(t-pi), x(0)=x'(0)=0 I am not sure how to do this problem... I found X(s) to be 2*e^(-pi*s)/(s^2+2s+2), but how do you do the laplace transform of 1/(s^2+2s+2)? Is there a laplace transform for functions with complex roots?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1/(s^2+2s+2) is on the s domain, so its already a transformed function. ¿did you mean the inverse transform for this function?
anonymous
  • anonymous
sorry I clicked on this kid's question and it was this basically when I did it, I came out with the wrong answer and was looking for some help
anonymous
  • anonymous
would you know how to do this?

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anonymous
  • anonymous
Find the inverse transform for 1/(s^2+2s+2)?
anonymous
  • anonymous
well eventually you would take the inverse laplace transform of : (2e^(-pi*s))/(s^2+2s+2)
anonymous
  • anonymous
so I got that far, and how did the inverse turned out to be wrong
anonymous
  • anonymous
First, ¿are you sure about the laplace transform of delta function?

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