anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
(p-2)^=16
anonymous
  • anonymous
is it \((p-2)^2=16\)?
anonymous
  • anonymous
yess

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anonymous
  • anonymous
ok then if \(p-2)^2=16\) you know that \(p-2=4\) so \(p=6\) or \(p-2=-4\) so \(p=-2\)
anonymous
  • anonymous
in other words you get two possible answers, either \(p=6\) or \(p=-2\)
anonymous
  • anonymous
ohh okay got it. Thank you

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