anonymous
  • anonymous
can anyone help?????? nerd in NEED! what is x3-x2-2x/x5-2x4-3x3 in simplest terms???
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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lgbasallote
  • lgbasallote
maybe factoring out the x in the numerator and denominator can help..yes?
anonymous
  • anonymous
it might see these are the answer choices..... a. 1/(x-3)(x+1) b. 1/x2(x-1) c. x-2/x2(x-1) d. -1/x2
Callisto
  • Callisto
\[( x^3-x^2-2x)/(x^5-2x^4-3x^3)\] First, take out the common factors \[x( x^2-x-2)/x^3(x^2-2x-3)\] Then, do the factorization \[x( x-2)(x+1)/x^3(x-3)(x+1)\] Can you work out the answer your own? (Note that i don't think any of the above choices are correct.. :S )

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anonymous
  • anonymous
well my teacher taught to like reduce the powers from top to bottom is that right????
Callisto
  • Callisto
What do you mean by ' reduce the powers from top to bottom'?
anonymous
  • anonymous
i mean like well.....im not sure she......its kinda confusing to explain... like take away an "x" 4rm the top like how the problem is one of the xs is x3 and the is x5 by taking an x away u would have no x on the top???? i dont know im confused...
Callisto
  • Callisto
Actually, i think it is like this Just take a look at the numerator, x^3-x^2-2x You can see every term contain an 'x', that is the common factor, so take is out and group it like x(x^2 - x -2x) Do you understand this part?
anonymous
  • anonymous
yes :)
Callisto
  • Callisto
Sorry, i made a mistake. It should be x(x^2 - x -2) . Well can you do the same for the denominator? Take out the common factor of x^5-2x^4-3x^3
anonymous
  • anonymous
its ok yeah i think i can
anonymous
  • anonymous
so would the denominator be x^3(x^2-2x-3)?
Callisto
  • Callisto
Yes
Callisto
  • Callisto
So next, you need to do factorization. Take a look at the denominator again, you can further factorise it x(x^2 - x -2), consider (x^2 - x -2) |dw:1333510991772:dw| So, (x^2 - x -2) = (x-2)(x+1) x(x^2 - x -2) = x(x+1)(x-2) Do you understand this part?
anonymous
  • anonymous
yeah i've gotten to the part where i cancel x+1 and x+1 but since none of the answer choices are there do i just keep the answer i go????? even though its a pratice book for the CST's?????
Callisto
  • Callisto
Perhaps you can write down the answer you get and ask your teacher?
anonymous
  • anonymous
ok :) thnx
Callisto
  • Callisto
Welcome!

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