A baseball is thrown with a vertical velocity of 50 ft/s from an initial height of 6 ft. The height h in feet of the baseball can be modeled by h(t) = -16t2 + 50t + 6, where t is the time in seconds since the ball was thrown. It takes the ball approximately _____ seconds to reach its maximum height. (Round to the nearest tenth of a second and enter only the number.)
To the nearest foot, what is the maximum height that the ball reaches? (Enter only the number.)
A player hits a foul ball with an initial vertical velocity of 70 ft/s and an initial height of 5 feet. The maximum height reach

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same deal as the other 2

this time instead of plugging in -50/[2(-16)], your answer is -50/[2(-16)]

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