anonymous
  • anonymous
how do you solve arctan[tan(-7pi/9)] ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
-7pi/9
anonymous
  • anonymous
isn't it outside of the domain? So you have to find another angle...
anonymous
  • anonymous
arctan( tan x)=x

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anonymous
  • anonymous
\[\tan^{-1}(\tan(x))=x\] arctan and tan are inverses
anonymous
  • anonymous
yea
anonymous
  • anonymous
the answer has to be within the domain\[-\pi/2\le \theta lepi/2\]
anonymous
  • anonymous
?
anonymous
  • anonymous
thats not the domain of tangent. the domain of tangent is all reals except k*pi/2, where k is an integer
anonymous
  • anonymous
oh, you want the reference angle
anonymous
  • anonymous
i see
anonymous
  • anonymous
yes please!
anonymous
  • anonymous
so the answer would be 2pi/9?
anonymous
  • anonymous
lol im sleepy, my brain is not working right now
anonymous
  • anonymous
gotcha lol same here. the reference angle would be in the first quadrant yes? and the angle would be 2pi/9
anonymous
  • anonymous
but wouldn't it have to be positive for an angle of -7pi/9 to exist? so the original angle would be in the third quadrant

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