anonymous
  • anonymous
The perimeter of rectangle is 80 inches...the area is 396 square inches...find length and width
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
lgbasallote
  • lgbasallote
perimeter of rectangle = 2L + 2W = 80 area = LW = 396 you can use substitution to solve...need guide?
anonymous
  • anonymous
i think i can get it
lgbasallote
  • lgbasallote
just tell me when you need help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i dont understand what you plugin for L & W
anonymous
  • anonymous
2L + 2W = 80 LW = 396 for LW = 396 L=396/W put this into 2L + 2W = 80 2(396/W) + 2W =80 396/W + W =40 396 +W^2 = 40W W^2 -40W -396 =0 solve for W, reject -ve value of W Then sub the value of W into L=396/W to find L Is the above what you mean, @lgba
anonymous
  • anonymous
thanks coco...thats it!

Looking for something else?

Not the answer you are looking for? Search for more explanations.