anonymous
  • anonymous
The block of glass (n=1.5) shown in cross section in the figure below is surrounded by air. A ray of light enters the block at its left-hand face with incident angle θ1 and reemerges into the air from the right-hand face directed parallel to the block’s base. Determine θ1.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1333520445384:dw|
mos1635
  • mos1635
|dw:1333527578619:dw| sinθ1/sinθ2 =1.5/1 sinθ3/sin θ4=1/1.5 θ2+θ3+90+45=180
mos1635
  • mos1635
find what Θ4 must be for the oytgoing ray to be parallel... and go to θ1.....

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anonymous
  • anonymous
|dw:1333552880630:dw| wat mos has done is use of snells law which says sin=r.i r.i is refractive index and i and r anre incident and refractive angles we have to be careful while choosing our normal (it should be perpendicular to the plane of glass surface) just like wat mos has beautifully depicted...

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